Question

Coffee costing Rs 250per kg was mixed with chicory costing Rs 75 per kg in the ratio 5:2 for a certain blend .If the mixture was sold at Rs 230 per kg,find the gain or loss percentage

Answer 1

Soln: Let 5kg of coffee be mixed with 2kg of chicory

CP of the mixture =₹(250×5+ 75×2)

= ₹ ( 1250 + 150 )

= ₹ 1400

SP of the mixture = ₹ ( 7 × 230 )

= ₹ 1610

Since SP > CP, gain

Gain = SP – CP

= ₹ ( 1610 – 1400 )

= ₹ 210

$gain \: \% = (\frac{gain}{cp} \times 100)\% \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( \frac{210 }{1400} \times 100)\% \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15\%$

Hope it help you

Answer 2

$\huge\underline\mathbb{SOLUTION:-}$

Let as consider x as the common multiple.

Cost of 5Kg of coffee:

$\implies$5x = 5 × 250 = Rs.1250

Cost of 2Kg of coffee:

$\implies$2x = 2 × 75 = Rs. 150

$\underline\mathsf\red {Therefore \: :-}$

The cost of the mixture is:

$\implies \mathsf {5x + 2x = 1250 + 150}$

$\implies \mathsf {7x = 1400}$

$\implies \mathsf {x = \cancel{\dfrac{1400}{7}} = 200}$

So, C.P of mixture = 200

S.P of mixture = 230

Since, S.P is more than C.P So, its Gain.

Gain = S.P - C.P

$\implies \mathsf {230 - 200 = Rs.\:30}$

$\implies \mathsf {Gain\% = \frac{(Gain \times 100)}{C.P} }$

$\implies \mathsf {\frac{(30 \times 100)}{200} }$

$\implies \mathsf {15\% }$

Therefore,

• The Gain Percent is 15%.