Question

cofficent of x^2 in 2/3√2x^2+17/2​

Answer 1

Answer:

2/3√2 is the answer

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Answer 2

Answer:

$</strong><strong>Gi</strong><strong>ven \: expression = \frac{2 \sqrt{2} }{3} {x}^{2} + \frac{17}{2}$

$coefficent \: of \: {x}^{2} = \frac{2 \sqrt{2} }{3}$