coil with an average diameter of 0.02 is placed perpendicular to a magnetic field of 6000 t if the induced e m f s11 voltage when magnetic field is charge 2 to 1000 time 4 second what is the the number of turns in the coil
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Answer:
The number of turns in the coil is 28.
Explanation:
It is given that,
Diameter of the coil, d = 0.02 m
Radius, r = 0.01 m
Initial magnetic field,
Final magnetic field,
Induced emf, E = 11 V
Time, t = 4 s
The expression for the induced emf is given by :
= magnetic fluxN = 28
So, the number of turns in the coil is 28. Hence, this is the required solution.
I hope it help for you
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