Question

coin.
A bag contains 5 white and 6 black balls and another bag contains 4 white and 3 black balls. A ball
is drawn from the first bag and without seeing its colour is put in the second bag. Find the
probability that if now a ball is drawn from the second bag it is black in colour.​

Answer 1

Step-by-step explanation:

the probability of drawing white ball from the first bag is 5/11 and black ball is 6/11

which doesn't count but once it goes to the second bag the probability of pulling a black ball will be either 3 or 4 / 8

let 1st outcome = 3/8 , 2nd = 4/8

as we donot know if the ball drawn from the first bag is black or white.

Now we can apply the law of probability

1st outcome of 1st bag × 1st outcome of black ball 2nd bag + 2nd outcomes of 1st bag× 2nd outcome of black balls in 2nd bag.

5 × 3 + 6 × 4

11 8 11 8

= 15 + 24

88 88

= 39/88