Question

Coin is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.

Answer 1

Answer:    57.04m

Explanation:

initial velocity (u) = 0

acceleretion (g) = 9.81  

time (t) = 3.41

now,

s = ut + (1/2)at^2

s = 0 * 3.41 + 0.5 * 9.81 * (3.41)^2

hence, depth = 57.04 m