Question

Coins of 1, 2 and 5 rupees are tossed. what is the probability of getting head on the 1 rupee, tail on the 2 rupee and a head on the 5 rupee coins?

Answer 1

Given,

Three coins are tossed.

To Find,

Probability of getting head on the 1 rupee, tail on the 2 rupees, and head on the 5 rupee coin.

Solution,

The formula for calculating the probability of an event is

Probability of an event = Favorable outcomes/total outcomes

In this case,

Favorable outcomes = 1 {H,T,H}

Total outcome = 2³ = 8

So,

Probabiltiy = 1/8

Hence, the probability of getting head on the 1 rupee, tail on the 2 rupees, and head on the 5 rupee coin is 1/8.

Answer 2

Concept:

Probability is how likely an event will occur ina time of span. This prediction will always has to be true.

Given:

Coins of $1,2,5$ rupees are tossed.

Find:

The probability of getting head on the $1 rupee$, tail on the $2rupee$ and a head on the $5rupee$ coins.

Solution:

According to the problem,

Sample space is $[H,T,H]$

There are two heads, one tail and the total smaple space is three.

So getting head or tail is $\frac{1}{2}$

Thus, getting head on the $1 rupee$ is $\frac{1}{2}$

Getting tail on the $2rupee$ is $\frac{1}{2}$

Getting head on the $5rupee$ is $\frac{1}{2}$

Thus, probability is $\frac{1}{2}*\frac{1}{2}*\frac{1}{2}=\frac{1}{8}$

Hence, the probability of getting head on the $1 rupee$, tail on the $2rupee$ and a head on the $5rupee$ coins is $\frac{1}{8}$