coins of same size are placed one above the other and a cylindrical solid block is formed.the volume of this block is 49.28 cm cube.diameter of each coin is 2.8 cm and thickness is 0.2 cm. find the number of coins arranged in this block
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Cylinder
volume = 49.28 cm³
Coin
d = 2.8 cm
so r = 2.8/2 = 1.4 cm
h = 0.2 cm
volume = r²h
= 22/7 * 1.4 * 1.4 * 0.2
V = 1.232 cm²
No. coins = 49.28/1.232 = 40 coins
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