Math, asked by tabhisheksir20, 5 months ago

coins were 200, find the number of coins of each denomin
10n.
12. The perimeter of a rectangular field is 80 m. If the length of the field is decreased by 2 m and breadth is
increased by 2 m, the area is increased by 36 m². Find its length and breadth.
Rashmi's garden is now a square. If she enlarges it by increasing the width 1 metre and the length​

Answers

Answered by chaudharynida12
1

Answer:

2(l+b)= 80m

l+b =80/2

l+b= 40m

l = 40- b

area = b(40-b)= 40b-b^2

if b increased by 2m = b+2

if l is decreased by 2m = l-2

=40-b-2

=38-b

area increased by 36m = 40b-b^2+36

area=l×b

40b-b^2+36 =(38-b)(b+2)

36b-40b = 36-76

-4b= -40

b= -40/-4

b= 10m

length=40-10m

= 30m

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