Col. the no. of moles of
methene reg to produce
33 gm of congas on its
complete combi
Answers
Answered by
3
Answer:
CH
4
+O
2
⟶CO
2
+2H
2
O
Gram molecular mass of CO2 = 12 +2(16) = 44g/mol
From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
Therefore moles of CH
4
required to produce 22g of CO
2
are:
=
44
1
×22=0.5 mol
Answered by
0
Answer:
CH
4
...........
........
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