Question

Col. the no. of moles of
methene reg to produce
33 gm of congas on its
complete combi​

Answer 1

Answer:

CH

4

+O

2

⟶CO

2

+2H

2

O

Gram molecular mass of CO2 = 12 +2(16) = 44g/mol

From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.

Therefore moles of CH

4

required to produce 22g of CO

2

are:

=

44

1

×22=0.5 mol

Answer 2

Answer:

CH

4

...........

........