Chemistry, asked by amandurge2005, 7 months ago

Col. the no. of moles of
methene reg to produce
33 gm of congas on its
complete combi​

Answers

Answered by Anonymous
3

Answer:

CH

4

+O

2

⟶CO

2

+2H

2

O

Gram molecular mass of CO2 = 12 +2(16) = 44g/mol

From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.

Therefore moles of CH

4

required to produce 22g of CO

2

are:

=

44

1

×22=0.5 mol

Answered by mahijknow2020
0

Answer:

CH

4

...........

........

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