Colin buys a tv for £800.
It depreciates at a rate of 1% per year.
How much will it be worth in 2 years?
Give your answer to the nearest penny where appropriate
Answers
Answered by
3
Answer:
HOPE THIS HELPS YOU!
Step-by-step explanation:
Given:
The cost of the T.V. for Colin = £ 800.
The rate of depreciation per year = 4%
Time period = 3 years
To find:
How much will it be worth in 3 years? Give your answer to the nearest penny where appropriate.
Solution:
To solve the above-given problem, we will use the following formula:
\boxed{\boxed{\bold{A = P [1 - \frac{R}{100} ]^n}}}A=P[1−R/100]n
where
A = the final value after depreciation
P = the present value
R = rate of depreciation
n = time period
Now, on substituting the given values in the formula, we get
A=P[1-R\100]^n
A=800×[1-1/100]^2
A=800×[100-1/100]^2
A=800×[99/100]^2
A=800×[0.99]^2
A=800×0.9801
A=784.08
A=784£
therefore, the worth of TV in 2 years is 784£.
Answered by
4
Answer:
£784.08
Step-by-step explanation:
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