Physics, asked by sna93, 11 months ago

Columbus law in vector form derivation​

Answers

Answered by Darkblaze123
10

ANSWER

Coulomb's law state us that electrostatic force b/w any two charges q and q' seperated by distance r is directly proportional to the product of the magnitude of the charges and inversely proportional to the square of the distance b/w them. In vector formthere will multiplication of r^.

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pankaj2022: abe vector form pucha h Coulams low nhi
sna93: I needed the derivation in vector form however I know this definition
sna93: thanks for trying
pankaj2022: okkk..
Answered by Anonymous
6

HERE IS YOUR ANSWER.

Vector Form of Coulomb’s Law

Vector Form of Coulomb’s LawThe physical quantities are of two types namely scalars (with the only magnitude) and vectors (those quantities with magnitude and direction). Force is a vector quantity as it has both magnitude and direction. The Coulomb’s law can be re-written in the form of vectors. Remember we denote the vector “F” as F, vector r as r and so on.

Let there be two charges q1 and q2, with position vectors r1 and r2 respectively. Now, since both the charges are of the same sign, there will be a repulsive force between them. Let the force on the q1 charge due to q2 be F12 and force on q2 charge due to q1 charge be F21. The corresponding vector from q1 to q2 is r21 vector.

r21 = r2 – r1

r21 = r2 – r1To denote the direction of a vector from position vector r1 to r2 , and from r2 to r1 as:

(refer to attachment )

Now, the force on charge q2 due to q1, in vector form is:

(refer to attachment )

The above equation is the vector form of Coulomb’s Law.

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sna93: it is too big cannot go through such big answer and and the answer to my question comprises just a page
pankaj2022: what?
Anonymous: have a look once again ..
Anonymous: if it helps uh !!
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