Question

Com a body starting from rest and moving with constant acceleration covers a distance s1 in the 4th second and a distance s2 in the 6th second . the ratio of s1÷s2.

Answer 1

Snth= u+a/2*(2n-1) So s1= 7a/2 and s2= 11a/2 and s1/s2= 7/11.

Answer 2

Answer:

7:11

explanation: using

snth=u+a/2(2n-1)

s=0+a/2(2×4-1)=7a/2

s=0+a/2(2×6-1)=11a/2

s1:s2=7:11