Com./Programme/2nd Sem./Englist/ALENGLCC2/2020
disability, crafted by agencies responsible for securing the rights of perso
disability, such as the government, are thus only frameworks for efficien
implementation and fulfillment of legal mandates. An understanding
nuance has largely been missing in active implementation of policy t
Nowhere is a conflict more evident than in the case of rare conditions or
conditions that very few individuals in a population have.
Write a letter to your friend about your difficulties in coping up with
normal due to the pandemic.
Write a letter to the editor of a newspaper expressing your views on th
youth in promoting gender equality to prevent trial
Answers
Answer:
though it is a c for class of a person to have the
Given:
Length of Rectangle = 40 cm
Breadth of rectangle = 10 cm
\sf Area_{\;(square)} = Area_{\;(rectangle)}Area
(square)
=Area
(rectangle)
⠀⠀
To find:
Perimeter of square?
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☯ Let side of square be x cm.
⠀⠀⠀
\begin{gathered}\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}\\ \\\end{gathered}
★Accordingtothequestion:
\sf Area_{\;(square)} = Area_{\;(rectangle)}Area
(square)
=Area
(rectangle)
⠀⠀
We know that,
⠀⠀
\sf Area_{\;(square)} = (side)^2Area
(square)
=(side)
2
\sf Area_{\;(Rectangle)} = length \times breadthArea
(Rectangle)
=length×breadth
⠀⠀
Therefore,
⠀⠀
\begin{gathered}:\implies\sf side \times side = length \times breadth\\ \\\end{gathered}
:⟹side×side=length×breadth
\begin{gathered}:\implies\sf x \times x = 40 \times 10\\ \\\end{gathered}
:⟹x×x=40×10
\begin{gathered}:\implies\sf x^2 = 400\\ \\\end{gathered}
:⟹x
2
=400
\begin{gathered}:\implies\sf \sqrt{x^2} = \sqrt{400}\qquad\quad\bigg\lgroup\bf Squaring\;both\;sides \bigg\rgroup\\ \\\end{gathered}
:⟹
x
2
=
400
⎩
⎪
⎪
⎪
⎧
Squaringbothsides
⎭
⎪
⎪
⎪
⎫
\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{x = 20}}}}}\;\bigstar\\ \\\end{gathered}
:⟹
x=20
★
\therefore\;{\underline{\sf{Side\;of\;square\;is\;{\textsf{\textbf{20\;cm}}}.}}}∴
Sideofsquareis20cm.
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Now, Finding Perimeter of square,
⠀⠀
\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}
†
Asweknowthat,
\begin{gathered}\star\;{\boxed{\sf{\pink{Perimeter_{\;(square)} = 4 \times side}}}}\\ \\\end{gathered}
⋆
Perimeter
(square)
=4×side
\begin{gathered}:\implies\sf Perimeter_{\;(square)} = 4 \times 20\\ \\\end{gathered}
:⟹Perimeter
(square)
=4×20
\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(square)} = 80\;cm}}}}}\;\bigstar\\ \\\end{gathered}
:⟹
Perimeter
(square)
=80cm
★
\therefore\;{\underline{\sf{Perimeter\;of\;square\;is\;{\textsf{\textbf{80\;cm}}}.}}}∴
Perimeterofsquareis80cm.
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\begin{gathered}\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:Formulas\:related\:to\:it\:\bigstar}}}} \\ \\\end{gathered}
★Formulasrelatedtoit★
\begin{gathered}\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Area\ formula&\bf Perimeter\ formula\\\cline{1-3}\sf Square&\tt side \times side}&\tt 4 \times side\\\cline{1-3}\sf Rectangle&\tt length \times breadth&\tt 2(length + breadth)\\\cline{1-3}\sf Triangle&\tt \dfrac{1}{2} \times base \times height&\tt sum\of\ all\ sides\ of\ \triangle\\\cline{1-3}\end{array}\end{gathered}