combination of 3digit number between 0 to 9
you 10x9x8 = 720 in all.
If what you actually want is what you said - combinations - that's something quite different. It is the number of ways to choose 3 of the 10 digits in which order is not important. There are 6 = 3x2x1 ways to order 3 digits in a row. Thus the number of combinations of 3 of the 10 digits is 720/6 = 120 combinations.
Hope this helps,
If what you actually want is what you said - combinations - that's something quite different. It is the number of ways to choose 3 of the 10 digits in which order is not important. There are 6 = 3x2x1 ways to order 3 digits in a row. Thus the number of combinations of 3 of the 10 digits is 720/6 = 120 combinations.
Hope this helps,
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123,456,752,674,597 etc.
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It's possible to generate all possible combinations of 3 digits by counting up from 000 to 999, but this produces some combinations of digits that contain duplicates of the same digit (for example, 099). I could obtain all combinations of 3 digits without repetition by counting up from 000 to 999, and then removing all numbers with duplicate digits, but this seems inefficient.
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If what you want are all possible three digit numbers with no repetition of the digits then you have 10 choices for the first digit, you have 9 choices for the 2nd digit, and you have 8 choices for the 3rd digit giving