Combinatorics
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How many different solutions are here
Are you familiar with +/- sign , it's same we use in Shridharacharya quadratic formula to write 2 solution at once
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Answer:
5040
Step-by-step explanation:
The answer is 7! = 5040
Let us understand why we have taken factorial here :-
Assume you have three boxes A, B, and C.
How many ways can we place them on top of each other?
It's 6 times
C(A, B, C)
C(A, C, B)
C(B, A, C)
C(B, C, A)
C(C, B, A)
C(C, A, B)
This is nothing but 3! = 6
By taking this simple example we can solve this problem
In total we have seven number of 2's and its value can either be '+' or '-'.
So from the before example, the blocks can either be placed on top, bottom or the middle.
In here the '+' and '-' signs can be placed in any non-repeating order just like the blocks.
Hope this solution helps:)
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