combine 2 ohm, 3 ohm, 6 ohm in such a way that total resistance is 2 ohm
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Assuming we have just one discrete resistor each of the three resistances given, we can combine them according to the following steps into a simple series/parallel network combination to make a 4 ohm resistance:
1: Put 3 ohms in parallel with 6 ohms to produce an equivalent of 2 ohms by the parallel equivalent resistance rule [1/(1/3 + 1/6) = 2]
2: Place that parallel combination in series with the other 2 ohms to get 4 ohms, since series resistances simply add [2+2=4]. The resulting series/parallel hybrid combination achieves the required equivalent resistance, which can be expressed more simply in the following form (3 ohms)//(6 ohms) + 2 ohms = 4 ohms.
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harsh1772:
but we have to make total resistance 2 ohm
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