Question

Combustion of 3 moles of C3H8 will produce how many moles of wate ​

Answer 1

Answer:

Whenever any organic compound undergoes combustion in excess oxygen, it releases carbon dioxide along with water in different ratios.

These ratios depend on the balanced chemical equation and number of moles of the reactant.

Chemical Equation of combustion of Propane:

C₃H₈ + O₂ → CO₂ + H₂O

Balanced Chemical Equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Hence, based on the above equation, we can say that 1 mole of Propane reacts to give 3 moles of CO₂ and 4 moles of H₂O.

Hence if 3 moles of Propane reacts with excess oxygen, we get:

⇒ 1 mole of Propane = 4 moles of Water :: 3 moles of Propane = ? (x)

⇒ x = 3 moles × 4

⇒ x = 12 moles of H₂O.

Hence 3 moles of Propane would produce 12 moles of Water on combustion.

Answer 2

3 moles of Propane required to produce 12 moles of Water .

$\underline \orange{ \bf{ \: EXPLANATION \: }} \red:$

Chemical Equation of Combustion of Propane(C₃H₈) :

$\rm C_3H_8 + O_2 \: \longrightarrow \: CO_2 + H_2O$

Balanced Chemical Equation :

$\rm C_3H_8 + \red5 O_2 \: \longrightarrow\: \red3CO_2 + \red4 H_2O$

Finding no.of.moles of Propane required to produce 12 moles of Water :

Hence, It shows that 1 mole of Propane Produces 4 moles of Water .

➱ 1 mole of Propane : 4 moles of Water :: 12 moles of Water : ___ moles of Propane (let i assume as y )

⇒ y * 4 = 1 * 12

⇒ 4y = 12

⇒ y = 12/4

⇒ y = 3

HENCE, 3 Moles of Propane required to produce 12 moles of Water .