combustion of 6.4 gram of Ethylene glycol give 9.0g carbon dioxide and 6.0 gram of water. the molecular mass of Ethylene ethylene glycol is 62 .find empirical formula?
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Explanation:
The empirical formula is the simplest whole number ratio defining constituent atoms in a species (this is glib, I think I learned this definition when I was 15, and it has stuck!). Given this, the molecular formula is clearly not the empirical formula (why not?), but is a multiple of the empirical formula.
So the empirical formula of ethylene glycol is
CH3O
; this is the ratio of carbons to hydrogen to oxygen we would find if we tried to determine the composition of the stuff by experiment (i.e. empirically).
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