Question

Comment on the nature of roots of the equation
x2 + ax - 4 = 0.​

Answer 1

ANSWER:-

The given equation is x2+ax−4=0

Comparing given equation with ax2+bx+c=0

∴a=1,b=a,c=−4

The discriminant of the given equation is given by D=b2−4ac=a2−4×−4=a2+16

Clearly, D=a2+16>0 for all a∈R

Hence, the given equation has real and distinct roots.

$\green{hope \: it \: will \: help \: you}$

Answer 2

ANSWER:-

The given equation is x2+ax−4=0

Comparing given equation with ax2+bx+c=0

∴a=1,b=a,c=−4

The discriminant of the given equation is given by D=b2−4ac=a2−4×−4=a2+16

Clearly, D=a2+16>0 for all a∈R

Hence, the given equation has real and distinct roots.