Question

comment on the nature of the roots of the equation 6x^2+x-2 =0​

Answer 1

Answer:

a= 6 b=1 c=-2

D= bsquare -4ac

= 1×1 - 4× 6 × -2

= 1+48

=49

D is positive

ao root is real and unequal

Answer 2

Step-by-step explanation:

To find nature of roots we use Discriminant function

$Discriminant, \: D = {b}^{2} - 4ac$

$D = {1}^{2} - 4 \times 6 \times (- 2)$

$D =1 + 48$

$D = 49$

Since, the discriminant is positive hence the roots will be real and distinct