Comment on the nature of the roots of the equation without solving: x²-ax-b²=0
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Discriminant, D = B²- 4(A)(C)
= (-a)² - 4(1)(-b²)
= a²-4b²
(a+2b)(a-2b)
Therefore, Equation'll have distinct roots.
= (-a)² - 4(1)(-b²)
= a²-4b²
(a+2b)(a-2b)
Therefore, Equation'll have distinct roots.
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