Question

Comment upon the nature of roots
I) 2x²-3x+5
ii) 3x+25/3x=0
Plz help
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Answer 1

Step-by-step explanation:

In a equation, ax² + bx +c,

∆ = b² - 4ac

If ∆ = 0, the roots are real and equal

If ∆ > 0, the roots are real and unequal

If ∆ < 0, the roots are unreal

(I) 2x² - 3x + 5

∆ = (-3)² - 4(2)(5)

= 9 - 40

= -31

∆ < 0, the roots are unreal

(II) $3x + \frac{25}{3x} = 0$

$\frac{9 {x}^{2} + 25}{3x} = 0$

$9 {x}^{2} + 25 = 3x$

$9 {x}^{2} - 3x + 25 = 0$

∆ = (-3)² - 4(9)(25)

= 9 - 900

= -891

Since ∆ < 0, the roots are unreal

Answer 2

-891 is u answer.

OK dear... nice day