Question

Commercial available Conc. HCL contains 38% HCL by mass.
(a)
What is the molarity of this solution. (density is 1.19g/cm)?
(b)
What volume of Conc. HCL is required to make 1L of 0.10M HCL ?​

Answer 1

Answer:

density of solution = 1.19 glml  

Molarity =  

1.19/MolarmassofHCl  ×1000×38%

=  

1.19/36.5 ×1000× 38/100 = 12.389m

mole of HCl required to make 10 L of all 0.1M HCl=10×0.1= 1 mole

12.389×v=1

v=  1/12.389

=80.7ml

Explanation:

HOPE it helps