Question

commercially available concentrated hydrochloric acid contains 38% HCL by mass (H=1,CL=35.5)
a)what is the molarity of the solutuon (density=1.19gml-1)
b) what volume of concentrated HCL is required to make1.0L of an 0.10M HCL​

Answer 1

Answer:

(a)12.34M (b) 8..08ml

Explanation:

(a)38%HCl by mass means 100g of HCl solution contain 38g of HCl by mass.

hence, wt.of soluteHCl = 38g

no of moles of HCl = 38g/36.5g/mol

= 1.04mol

volume of solution= mass/density= 100/1 .19ml

molarity of HCl solution=n/vol.= 1.04×10×1.19M

= 12.37M

(b)using M1V1 =M2V2

volume of HCl =( 1L)×(0.10M)/12.37M = 8.08 ml