Question

commercially available concentrated hydrochloric acid contains 38 % HCL by mass if the density is 1.19 g/ml find molarity

Answer 1

Let there be 1L. of this solution. 
Mass of solution : 1.19 * 1000 = 1190 g
Further, % of HCl in this solution :
                            = $\frac{38}{100}$ * 1190
                            = 452.2 g.
We know that : 
                           1 mole HCl       weighs         36.5 g
                           "x" moles HCl   weighs        452.2 g
moles of HCl = 452.2 g *$\frac{1 mole HCl}{36.5 g HCl}$
                      = 12.389 moles 
  So, we have obtained that 12.39 moles of HCl are present in 1L of solution. Hence
                                Molarity (M) = $\frac{12.39 moles}{1L}$
                                Molarity (M) = 12.39 moles/L

Answer 2

Mark my answer as BRAINLIEST .