Question

Commercially available concentrated Hydrochloric Acid contains 38 % HCl by mass. What volume of concentrated HCl is required to make 1.0 L of an 0.10 M HCl. [ Density of solution is = 1.29 g / ml ]​

Answer 1

Answer:

Commercially available conc. HCl contains 38% HCl by mass, what is the molarity of the solution, density of solution = 1.29g/ml. What volume of conc. HCl is required to make 10.L of an 0.10 M HCl

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Density of solution = 1.19 glml

$Molarity = \frac{1}{molar \: mass \: of \: hcl} \times 1000 \times 38\%$

$= \frac{1.19}{36.5} = 1000 \times \frac{38}{100}$

=12.389m

$= 0.1m \: hcl = 10 \times 0.1 = 1mole$

$12.389 \times v = 1$

$v = \frac{1}{12.389} = 80.7ml$

Hence, This is answer