Commercially available hcl contains 38% hcl by weight density 1.19 gram per centimetre cube find the molarity
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Answer: 12.3 M
Explanation:
we consider that have 1000g of this solution
v = 1000/1.19 ⇒ v= 0.84 L
1000*0.38/36.5= 10.41 mol HCl
10.41/0.84=12.3M
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