common difference = 4 7th term= 30 algebraic form of this sequence
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Step-by-step explanation:
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Answer:
4n+2 is the algebraic form of this sequence.
Step-by-step explanation:
Algebraic form = dn+f-d
d = common difference = 4 (given)
f = first term = x₁ = x₇ - 6d = 30 - 6 × 4 = 30 - 24 = 6 (x₇ is the 7th term)
∴ Algebraic form of this sequence = dn+f-d = 4n + 6 - 4 = 4n+2
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