Question

Common difference of an arithmetic sequence is 1 and the product of the first and third terms is 143 .what are first 3 terms

Answer 1

Answer:

First term of the sequence is 10 and common difference is 3.

a1= 10 and d = 3

Next term = a2

=a1+d=10+3=13

a3=a2+d=13+3=16

Thus, first three terms of the sequence are 10, 13 and 16.

Let 100 be the nth term of the sequence.

an =a

1+(n−1)d

100=10+(n−1)3

90=(n−1)3

n−1=30

n=31, which is a whole number.

Therefore, 100 is the 31 st term of the sequence.