Common difference of an arithmetic sequence is 10 and its 6th term is 52 find out 15th term
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15th term of the AP is 142
Step-by-step explanation:
first term = a
common difference = d = 10
nth term an = a + (n-1)d
6th term = a + (6-1)10 = 52
a + 5×10 = 52
a + 50 = 52
a = 52 - 50
a = 2
15th term = a + (n-1)d
= 2 + (15-1)10
= 2 + (14×10)
= 2 + 140
= 142
therefore the 15th term of the AP is 142
Hope you get your answer
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