Question

Common difference of an arithmetic sequence is 5 and it's 10th term 50. Find it's 20th term ​

Answer 1

$common \: difference = 5$

$a 10 = 50$

$a + (n - 1)d = an$

$so \: a10 = a + 9 \times 5$

$a = 5$

$first \: term = 5$

$a20 = a + 19d$

$a20 = 5 + 19 \times 5$

$a20 = 100$

$20th \: term = 100$