Question

Common factor of 17abc, 34ab^2, 51a^2 b is

(a) 17abc
(b) 17ab
(c) 17ac
(d) 17a^2 b^2 c

Answer 1

$\huge\mathbb\red{Answer:-}$

Answer 2

Answer:

(b)17ab

Step-by-step explanation:

17abc=17*a*b*c

34ab²=17*2*a*b*b

51a²b=17*3*a*a*b

here we take minimum power of common factor

So, common factor is 17ab