Question

Common factor of 8abc, 32ab², 16a²b is _________.​

Answer 1

Answer:

The answer is $8ab$

Step-by-step explanation:

$8abc=2^3\times a\times b\times c$

$32ab^2=2^5\times a\times b^2$

$16a^2b=2^4\times a^2\times b$

Clearly the common factors is $2^3\times a\times b=8ab$

Answer 2

Answer:

8ab

Step-by-step explanation:

Let's factorize all the given factors:

8abc = 8 × a × b × c

32ab² = 8 × 4 × a × b × b

16a²b = 8 × 2 × a × a × b

Now clearly we see that 8, a and b are common in all the expands.

So, 8ab is the common factor.