Question

COMMON MONOMIAL FACTOR

Question
a2bc+ab2c+abc2

Answer 1

Answer:

common factor is - abc

hope it helps you!

Answer 2

Answer:

The solution for the above given equation is $a+b+c=0$ $a b c=0$

Step-by-step explanation:

Given:

A equation- $a^{2} b c+a b^{2} c+a b c^{2} .$

To Solve:

Find the solution of above given equation.

Solution:

Let, $P=a^{2} b c+a b^{2} c+a b c^{2}$

$\begin{aligned}&P=a^{2} b c+a b^{2} c+a b c^{2} \\&=a(a) b c+a b(b) c+a b c(c) \\&=a(a b c)+b(a b c)+c(a b c) \\&=(a b c)(a+b+c)\end{aligned}$

Hence,

$\begin{aligned}&P=(a b c)(a+b+c) \\&\mathbf{P}=\mathbf{0}\end{aligned}$

if either $a b c=0$

or $a+b+c=0$