common salt obtained from sea water contains 96% of NaCl by mass. the approximate no. of molecules present in 10.0 g of salt is
Answers
Answered by
86
Let 100g of sea water contains 96g of sodium chloride
So 10g of water would have 9.6 g of sodium chloride
Molar mass of sodium chloride is 35.5+23=58.5g
No of moles in 9.6 g of sodium chloride is 9.6/58.5 moles
No. Of molecules present would be 9.6/58.5*Avogadro number
So 10g of water would have 9.6 g of sodium chloride
Molar mass of sodium chloride is 35.5+23=58.5g
No of moles in 9.6 g of sodium chloride is 9.6/58.5 moles
No. Of molecules present would be 9.6/58.5*Avogadro number
proximaze:
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Answered by
38
Answer: molecules of NaCl
Explanation:-
Given: mass of salt = 10 g
But as salt contains 96% of NaCl by mass, amount of NaCl=
To calculate the moles, we use the equation:
Mass of NaCl = 9.6 g
Molar mass of NaCl= 58.5 g/mol
Putting values in above equation, we get:
According to Avogadro's law, 1 mole of every substance contains avogadro's number of particles.
Thus 0.16 mol of NaCl contains= molecules of NaCl.
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