common salt obtained from sea water contains 96% of NaCl by mass. the approximate no. of molecules present in 10.0 g of salt is
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Let 100g of sea water contains 96g of NaCl
So,10g of water would contain 9.6 g of NaCl
Now,molar mass of NaCl = 35.5+23=58.5g
No of moles in 9.6 g of NaCl is 9.6/58.5 moles
=> No. of molecules present = 9.6 / 58.5 x 6.023 x 10^23 = 9.87 x 10^22 molecules.
So,10g of water would contain 9.6 g of NaCl
Now,molar mass of NaCl = 35.5+23=58.5g
No of moles in 9.6 g of NaCl is 9.6/58.5 moles
=> No. of molecules present = 9.6 / 58.5 x 6.023 x 10^23 = 9.87 x 10^22 molecules.
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