Question

common tangents ab and cd to 2 circles intersect at e. prove that ab=cd​

Answer 1

Answer:

AB and CD are common tangents on both the circles. AB and CD intersect at E.

AB and CD are common tangents on both the circles. AB and CD intersect at E.Now, EA=EC (Tangents drawn on circle from same point)

AB and CD are common tangents on both the circles. AB and CD intersect at E.Now, EA=EC (Tangents drawn on circle from same point)EB=ED (Tangents drawn on circle from same point)

AB and CD are common tangents on both the circles. AB and CD intersect at E.Now, EA=EC (Tangents drawn on circle from same point)EB=ED (Tangents drawn on circle from same point)EA+EB=EC+ED,

AB=CD.

Step-by-step explanation:

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Answer 2

$\small{\underline{\underline{Correct \: Question →}}}$

In Figure , common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB = CD.

$\small{\underline{\underline{Solution→}}}$

From the given figure, AB and CD are common tangents on both the circles. AB and CD intersect at E.

Now, EA=EC (Tangents drawn on circle from same point)

EB=ED (Tangents drawn on circle from same point)

EA+EB=EC+ED

AB=CD

${\boxed{\boxed{\rm{\pink{→\bar{AB.}=CD✔}}}}}$