Question

Commonly
Asked Questions
A car of mass 1200 kg is moving on the road at the speed of 60 km/h.
If the coefficient of friction is 38 and the normal force is 50 N, the
frictional force acting on the car is given by?​

Answer 1

$\huge\mathcal\pink{Answer:-}$

★ Given:-

Speed=16m/s

Coeffi fric(u)=38

Normal reaction=mg downwards=50

To find out:friction

Formula:u×normal reaction

Sol:now the velocity and mass is just given to confuse us and is termed as superfluous data which is of no use as u can see from the formula

Therfore friction=u x mg

=50 x 38

=1900 N

As there is no need of any other information when the normal force is given as friction depends on normal reaction and not the velocity of an object.

Hope this helps!❤