Question

compaire x² - 13x + k = 0 with ax² + bx + c = 0 find a b c ​

Answer 1

$when \: comparing \\ {x}^{2} - 13x + k = 0 \\ = = > (1) {x}^{2} + ( - 13)x + k = 0 \\ a {x}^{2} + bx + c = 0 \\ \\ here \\ a = 1 \\ b = - 13 \\ c = k$