Question

Company Tesla has kept a contest for catchy caption for the image. They have a rule that the caption should not be more than 10 words. If the caption of a candidate is more than 10 words, then the candidature stands to be disqualified. Can you write a program to check whether a caption is eligible for the contest or not.
The maximum sizeof the caption is of 100 bytes.
[Hint:Use functions defined in cstring]

Answer 1

Answer:

#include <stdio.h>

#include <string.h>

int main()

{

  char s[200];

  int count = 0, i;

  scanf("%[^\n]s", s);

  for (i = 0;s[i] != '\0';i++)

  {

      if (s[i] == ' ' && s[i+1] != ' ')

          count++;    

  }

 if((count+1)<10)

   printf("Caption eligible for the contest");

else

     printf("Caption not eligible for the contest");

}

Explanation:

Answer 2

Answer:

//Using char array

#include <cstring>

#include <iostream>

using namespace std;

int main()

{

char str[100];

int len,count=0;

cin.getline(str,100);

len=strlen(str);

for(int i=0;i<strlen(str);i++)

if(str[i]==' ')

count++;

if(count+1>10)

cout<<"Caption not eligible for the contest";

else

cout<<"Caption eligible for the contest";

}

/*

// Using string class

#include <cstring>

#include <iostream>

using namespace std;

int main()

{

string str;

int len,count=0;

getline(cin, str);

for(int i=0;i<str.length();i++)

if(str[i]==' ')

count++;

if(count+1 >10)

cout<<"Caption not eligible for the contest";

else

cout<<"Caption eligible for the contest";

}*/

Explanation: