Question

Compare 3 x² + 2 √3 x + √3 = 0 with ax² + bx + c = 0 and find the value of b²-4ac. from this write the nature of roots.

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Answer 1

Answer:

See the explanation

Step-by-step explanation:

Comparing $3x^2+2\sqrt 3+\sqrt 3=0$ with $ax^2+bx+c=0$

we have $a=3,b=2\sqrt 3,c=\qrt 3$

$\therefore b^2-4ac=(2\sqrt 3)^2-4(3)(\sqrt 3)=12-12\sqrt 3=12(1-\sqrt 3)$

And since $\sqrt 3>1$$\Rightarrow b^2-4ac=12(1-\sqrt 3)<0$

and hence roots are unreal