Math, asked by Varzan, 11 months ago

compare 6x(7-x)=3 with ax²+bx+c=0 and find the value of a b and c

Answers

Answered by SRISHTIMALIK29
1

6x(7-x)=3

42x-6x^2-3=0

6x^2-42x-3=0

value of a=6,b=-42,c=-3

hope it helps you.

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Answered by srinibhasrikanth
0

Answer:

a=2

b=-14

c=1

Step-by-step explanation:

ax²+bx+c=0

6x(7-x)=3

2x(7-x)=1

14x - 2x²=1

2x²-14x+1=0

hence, a=2 b=-14 c= 1

hope it helped u

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