compare 6x(7-x)=3 with ax²+bx+c=0 and find the value of a b and c
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Answered by
1
6x(7-x)=3
42x-6x^2-3=0
6x^2-42x-3=0
value of a=6,b=-42,c=-3
hope it helps you.
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Answered by
0
Answer:
a=2
b=-14
c=1
Step-by-step explanation:
ax²+bx+c=0
6x(7-x)=3
2x(7-x)=1
14x - 2x²=1
2x²-14x+1=0
hence, a=2 b=-14 c= 1
hope it helped u
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