Question

Compare a = √15 +√11 , b = √ 14 + √ 12 ( hint : compare a square and b square)

Answer 1

${a}^{2} = 26 +2 \sqrt{165 } \\ {b }^{2} = 26 + 2 \sqrt{168}$

${(a + b)}^{2}$ so,a<b

Answer 2

Step-by-step explanation:

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