Compare acidic trend:-
m-fluorophenol............. m-chlorophenol
With appropriate reason...
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Heya user !!
Here's the answer you are looking for.
In both, m-fluorophenol & m-chlorophenol, resonance comes into play but since it is in meta position it has no effect in deciding the acidic character.
In m-fluorophenol, fluorine is present which is more deactivating, that means more electron withdrawing. So, the electron density in m-fluorophenol decreases.
Whereas, in m-chlorophenol, chlorine is less deactivating than fluorine, so the electron density decreases but not as m-fluorophenol.
Therefore, m-fluorophenol is more acidic.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for.
In both, m-fluorophenol & m-chlorophenol, resonance comes into play but since it is in meta position it has no effect in deciding the acidic character.
In m-fluorophenol, fluorine is present which is more deactivating, that means more electron withdrawing. So, the electron density in m-fluorophenol decreases.
Whereas, in m-chlorophenol, chlorine is less deactivating than fluorine, so the electron density decreases but not as m-fluorophenol.
Therefore, m-fluorophenol is more acidic.
★★ HOPE THAT HELPS ☺️ ★★
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But according to theory, acidic character is directly proportional to –I effect.
But u have to see all other aspects na like resonance and hyperconjugation which r dominating over inductive effect
The functional group is in meta position, resonance will have no effect on acidic character
Dear we can not change experimental results do we have to state any appropriate reason . Yaa hydrogen bonding can be a reason bcoz lone pair of cl an f are directed towards hydrogen
Hydrogen bond is not possible here
I know that ur ans is this only but if u ask it's genuine reason , it is H- bonding only bcoz consider the big big lone pair on chlorine and fluorine. Ya meta H bonding can be taken by on our own bcoz it is absurd too . But the reality
You cant change the theory just to make the experimental results same as theoretical ones
H bonding is possible when the electron donating group is present in the ortho position
Okay sure u r Right then give me reason
Any reason
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