Question

Compare frequency polygon with Histogram

Answer 1

frequency polygons are actually drawn using histograms

thus they cannot be compared as they have different structures

also they are linked together more or less they are same probably

Answer 2

frequency polygon with histogram

$\setlength{\unitlength}{1 cm}\begin{picture}(12,4)\thicklines\put(0.7,0.5){\sf0}\put(1,1){\circle*{0.1}}\put(1,1){\vector(1,0){8.8}}\put(1,1){\vector(0,1){6.8}}\put(1.7,0.5){\sf0.5}\put(2.7,0.5){\sf5.5}\put(3.7,0.5){\sf10.5}\put(4.7,0.5){\sf15.5}\put(5.7,0.5){\sf20.5}\put(6.7,0.5){\sf25.5}\put(7.7,0.5){\sf30.5}\put(0.5,1.9){\sf8}\put(0.5,2.9){\sf16}\put(0.4,3.9){\sf24}\put(0.4,4.9){\sf32}\put(0.4,5.9){\sf40}\put(0.4,6.9){\sf48}\put(2,1){\line(0,1){0.2}}\put(3,1){\line(0,1){0.5}}\put(4,1){\line(0,1){0.7}}\put(5,1){\line(0,1){1.3}}\put(6,1){\line(0,1){3.8}}\put(7,1){\line(0,1){5.6}}\put(8,1){\line(0,1){5.6}}\put(2,1.2){\line(1,0){1}}\put(3,1.5){\line(1,0){1}}\put(4,1.7){\line(1,0){1}}\put(5,2.3){\line(1,0){1}}\put(6,4.8){\line(1,0){1}}\put(7,6.6){\line(1,0){1} }\put(3,0.1){\vector(1,0){3.5}}\put(4.3,-0.3){\sf Frequency}\put(0.1,1){\vector(0,1){4.5}}\put(-0.17,4.6){\sf C }\put(-0.17,4.3){\sf L }\put(-0.17,4.0){\sf A }\put(-0.17,3.7){\sf S }\put(-0.17,3.4){\sf S }\put(-0.17,2.8){\sf M }\put(-0.17,2.5){\sf A }\put(-0.17,2.2){\sf R }\put(-0.17,1.9){\sf K}\multiput(0.9,1)(0,1){7}{\line(1,0){0.2}}\multiput(1,0.9)(1,0){8}{\line(0,1){0.2}}\put(2.5,1.2){\circle*{0.1}}\put(3.5,1.5){\circle*{0.1}}\put(4.5,1.7){\circle*{0.1}}\put(5.5,2.3){\circle*{0.1}}\put(6.5,4.8){\circle*{0.1}}\put(7.5,6.6){\circle*{0.1}}\qbezier(1, 1)(1,1)(2.5,1.2)\qbezier(2.5,1.2)(3.5,1.5)(4.5,1.7)\qbezier(4.5,1.7)(5.3,2.2)(5.5,2.3)\qbezier(5.5,2.3)(6.3,4.1)(6.5,4.8)\qbezier(6.5,4.8)(7.3,6.1)(7.5,6.6)\end{picture}$

Note : Kindly , see the answer through web .