compare highest and least resistance obtained by showing 2 combinations using 4 resistors 16 ohm each
Answers
Answered by
3
the highest resistance is obtained when they are connected in series and the lowest is obtained when they are connected in parallel
In series
Reff=R1+R2+R3+R4
=16+16+16+16
=64 ohm
In parallel
1/Reff=1/R1+1/R2+1/R3+1/R4
=1/16+1/16+1/16+1/16
=1/4
Reff=4 ohm
therefore
Highest/lowest=16/4
=4/1
Hope this helps.
Similar questions