Question

compare logs of two differet base eg:log(11)1650>log(13)1950 ?
in above example value in brackets have base values

Answer 1

$log_{11} 1650= \frac{log_{10} 1650}{log_{10}11}= \frac{3.2175}{1.0414}=3.09$
$log_{13} 1950= \frac{log_{10} 1950}{log_{10}13}= \frac{3.2900}{1.1139}=2.95$
therefore
$log_{11} 1650 > log_{13} 1950$