Compare the area of a rectangle of sides 14 half (like this) 1/2 and 8 half and a square of side 10 three / fourth . Which is greater and by how much ? answer: Rectangle :- 493/4msquare Square :- 1849/16 Answer :- 123/16 m square . How this answer is can you tell me please guys ;) without spamming from goggle , chrome and from any information resources give correct answer by ourselves
Answers
Step-by-step explanation:
Rectangle - length (l) = 14 1/2 m = 29/2 m
breadth = 8 1/2 m = 17/2 m
( To convert mixed fraction into improper fraction - Multiply the denominator with the whole number and add with the numerator - write this answer as the numerator and the denominator will remain same - example 14 1/2 = 14x2+1/2 = 28+1/2 = 29/2)
Area of rectangle = length x breadth = 29/2 x 17/2
= 29 x 17/ 2 x 2 = 493/4 square metres or
123 1/4 square metres (mixed fraction)
123 one fourth square metres
Square - Side = 10 3/4 m = 43/4 m
Area of square = (side x side) = 43/4 x 43/4
43x43/ 4x4 = 1849/16 square metres
115 9/16 square metres (mixed fraction)
Difference = 493/4 - 1849/16
= 493x4/4x4 - 1849/16 (LCM of denominator to subtract)
= 1972/16 - 1849/16 = 123/16 square metres
Area of rectangle is greater by 123/16 square metres.
I hope it helps.
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