Question

Compare the area of rectangle of length 10m and breadth 5m with that of a square of side 8m

Answer 1

GIVEN:

• Length of rectangle = 10m
• Breadth of rectangle = 5m
• Side of square = 8 m

TO FIND:

• Compare the area of rectangle and square

SOLUTION:

We know that the formula for finding the area of rectangle is:-

$\large{\boxed{\bf{\star \: AREA = Length \times Breadth \: \star}}}$

To find the area of the square, we use the formula:-

$\large{\boxed{\bf{\star \: AREA = (Side)^2 \: \star}}}$

According to question:-

$\large\bf{\star \: Length \times Breadth = (Side)^2 \: \star}$

On putting the given values in the formula, we get

$\rm{\hookrightarrow 10 \times 5 = (8)^2 }$

$\rm{\hookrightarrow 50 = 64 }$

Divide by '2' on both sides

$\bf{\hookrightarrow 25 = 32 }$

❝ Hence the comparison between the area of rectangle and square is 25 and 32 respectively. ❞

______________________

Answer 2

Given :

◾Length of rectangle = 10m

◾Breadth of rectangle = 5m

◾Side of square = 8 m

To Find :

◾Compare area of rectangle and square

Solution :

◾We know that the formula for finding the area of rectangle is:-

${\boxed{\sf{\green{Area~= Length \times Breadth }}}}$

To find the area of the square, we use the formula:-

${\boxed{\sf\red{ \: Area ~= (Side)^2 }}}$

According to question:-

$\sf\pink{Length \times Breadth = (Side)^2}$

◾On putting the given values in the formula, we get

$\sf{\dashrightarrow 10 \times 5 = (8)^2 }$

$\sf{\dashrightarrow 50 = 64 }$

◾Divide by 2 on both sides

$\sf{\dashrightarrow 25 = 32 }$

:${\implies{\underline{\boxed{\sf{\color{salmon}{25~=~32}}}}}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

$\sf\purple{\therefore{Hence~ the~ comparison ~between~ the}}$$\sf\purple{~area~ of~ rectangle ~and~ square~ is ~25~ and~ 32 }$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$