Math, asked by Priyanshik, 1 year ago

compare the area of rectangle of sides 29/2m and 35/4m which is greater and by how much.

Answers

Answered by kasyapanand7

For 1st rectangle:-
Sides = 29m , 2m
As,
Area of rectangle=product of adjacent sides
=29m*2m
=58m²
For 2nd rectangle:-
Sides = 35m , 4m
As,
Area of rectangle=product of adjacent sides
=35m*4m
=140m²
Now,
Area of 1st rectangle:Area of 2nd rectangle = 58 m² : 140 m²
= 58 ÷ 140
= 39/70
= 39:70
( Solved )

Saviturchauhan: hey u he has not asked ratio he asked for difference

Answered by Saviturchauhan

$hey \: u \: buddy \: here \: yours \: answer \: \\ area \: of \: rectangle \: with \: dimensions \: 29 \times 2 = 58 \\ now \: \\ area \: of \: rectangle \: with \: dimensions \: 35 \times 4 = 140 \\ since140 > 58 \\ by140 - 58 = 82 \\$
hopes this will help you
if you are satisfied with my answer plz mark me as brain list

kasyapanand7: Illitrate fellows don't knowing the meaning of compare,

Saviturchauhan: hey u would be illerate and fellow compare is done fractionally and by difference also u the hell

kasyapanand7: Then how can you say that i am wrong. And now don't disturb again.

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